what is the identity of cosA - cosB?
Answers
Answered by
10
HOLA FRIEND ❗❗❗
HERE'S THE ANSWER ✌
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Here is your formula:-
cos(A-B)=cos A cos B + sin A sin B
✔✔✔✔✔✔✔
__________________
hope it helps uuhh☺☺☺☺
HERE'S THE ANSWER ✌
_________________
⤵⤵⤵⤵⤵⤵
Here is your formula:-
cos(A-B)=cos A cos B + sin A sin B
✔✔✔✔✔✔✔
__________________
hope it helps uuhh☺☺☺☺
swetha137:
for eg: cos90 - cos60 is not equal to cos30
Answered by
1
Answer:
HI,
Step-by-step explanation:
E=cos(A)−cos(B)sin(A)+sin(B)
Multiplying the numerator and denominator by cos(A)+cos(B)
E=cos(A)−cos(B)sin(A)+sin(B)×cos(A)+cos(B)cos(A)+cos(B)
=cos2(A)−cos2(B)[sin(A)+sin(B)][cos(A)+cos(B)]
Using the identities cos2(A)=1−sin2(A) and cos2(B)=1−sin2(B)
E=1−sin2(A)−1+sin2(B)[sin(A)+sin(B)][cos(A)+cos(B)]
=sin2(B)−sin2(A)[sin(A)+sin(B)][cos(A)+cos(B)]
=[sin(B)−sin(A)][sin(B)+sin(A)][sin(A)+sin(B)][cos(A)+cos(B)]
Dividing the numerator and denominator by sin(A)+sin(B), we have:
E=sin(B)−sin(A)cos(A)+cos(B)
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