what is the last digit of 307^307?
nyx:
wat does the" ^ " sign mean?
Answers
Answered by
2
Hi,
If the last digit or digit at the units place of ' a ' is 7 then the last digit
of a^n depends upon the value of n
and follows repeating pattern
i ) a^4n+1 the last digit is 7
ii ) a ^ 4n+2 the last digit 9
iii ) a ^ 4n+3 the last digit 3
iv ) a ^ 4n+4 the last digit 1
( 307 )^307
= ( 307 ) ^ (4×76 + 3)
Now it is in the form a^4n+3
Therefore,
The last digit in the expansion of
(307 )^307 is 3
I hope this helps you.
:)
If the last digit or digit at the units place of ' a ' is 7 then the last digit
of a^n depends upon the value of n
and follows repeating pattern
i ) a^4n+1 the last digit is 7
ii ) a ^ 4n+2 the last digit 9
iii ) a ^ 4n+3 the last digit 3
iv ) a ^ 4n+4 the last digit 1
( 307 )^307
= ( 307 ) ^ (4×76 + 3)
Now it is in the form a^4n+3
Therefore,
The last digit in the expansion of
(307 )^307 is 3
I hope this helps you.
:)
Answered by
0
Answer: The answer is 3
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