what is the mass of1.204 *10^22 atoms of nitrogen
Answers
Answered by
0
Explanation:
So the 3.40⋅1022 helium atoms weigh 0.226 gram .
Answered by
0
Answer:
Mass of 6.022 × 10²³ atoms of N=14g
On dividing by 5 on both sides;
Mass of 6.022/5 ×10²³atoms of N=14/5g
Mass of 1.2044×10²³atoms of N=2.8g
On dividing by 10 on both sides:
∴ Mass of 1.2044×10²²atoms of N=0.28g
Similar questions