what is the molarity of hno3 if its density is 1.14 gcm-3 and percentage for purity is 37%
Answers
A liquid's specific gravity is simply the ratio between its density and the density of a reference liquid, more often than not water, at the same temperature.
Usually, the specific gravity for liquids is given at
4
∘
C
, the temperature at which water's density is at its maximum value of approximately 1 g/mL.
So, in other words, using the specific gravity of a concentrated nitric acid solution is simply another way of saying that its density is 1.42 g/mL.
S.G
=
ρ
H
N
O
3
ρ
water
⇒
ρ
H
N
O
3
=
S.G.
⋅
ρ
water
ρ
H
N
O
3
=
1.42
⋅
1 g/mL
=
1.42 g/mL
Now for the actual calculations. Select a 1.0-L sample of your stock solution, then use its density to determine what its mass is.
1.0
L
⋅
1000
mL
1
L
⋅
1.42 g
1
mL
=
1420 g
You also know the solution's percent concentration by mass to be 69%. This of cours implies that every 100 g of solution will contain 69 g of nitric acid.
The mass of nitric acid your sample contains will be
1420
g solution
⋅
69 g
H
N
O
3
100
g solution
=
979.8 g
H
N
O
3
Use nitric acid's molar mass to determine the number of moles you have
979.8
g
⋅
1 mole
63.01
g
=
15.55 moles
H
N
O
3
The solution's molarity, which is defined as the number of moles of solute, in your case nitric acid, divided by the volume of the solution - in liters - will thus be
C
=
n
V
=
15.55 moles
1.0 L
=
15.6 M
To get the solution's molality, which is defined s moles of solute per kilograms of solvent, you need to first figure out how much water you have.
m
sol
=
m
nitric acid
+
m
water
m
water
=
1420
−
979.8
=
440.2 g water
Therefore, the molality will be
b
=
n
nitric acid
m
water
=
15.55 moles
440.2
⋅
10
−
3
kg
=
35,3 molal
HOPE U WILL UNDERSTAND THIS PLZ BRAINLIEST ANS plzz.