Question

what is the momentum of a 39.2 N bowling ball with a velocity of 7.00m/s

Answer 1

Explanation: First, you must find the mass of the bowling ball, w = mg.  Mass is therefore w/g, or 39.2 N / 9.8 m/s², or 4.00 kg.  The momentum is then

p = mv

= 4.00 kg * 7.00 m/s

=28.0 kg*m/s in the direction of motion of the bowling ball.

Incidentally, a bowling ball must weigh between 10 and 16 pounds to be official.  The ball in this example is too light.

Answer 2

Answer:hi

Explanation: