what is the momentum of a 39.2 N bowling ball with a velocity of 7.00m/s
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Explanation: First, you must find the mass of the bowling ball, w = mg. Mass is therefore w/g, or 39.2 N / 9.8 m/s², or 4.00 kg. The momentum is then
p = mv
= 4.00 kg * 7.00 m/s
=28.0 kg*m/s in the direction of motion of the bowling ball.
Incidentally, a bowling ball must weigh between 10 and 16 pounds to be official. The ball in this example is too light.
donna8269:
very helpful, thanks
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Answer:hi
Explanation:
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