what is the normality of a solution of 0.285 mol of naoh dissolved in 250ml water
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Answer:
hi dear..
Explanation:
10 gram= 10^4 mg. 1 mg= 10 ^(-4) g. 10^(-4) g in 250mL solution will make 10^(-4) M solution or 0.0001 M solution.
Answered by
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Answer:N=gm wt/eq mass. *1000/vol(ml)
N=0.285*1000/250
N=1.14
Explanation:
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