What is the nth term of the sequence (2,-1,-4,-7)
Answers
Answered by
0
Answer:
tn=a+(n-1)d
t4=2+(n-1)-3
t4=2-3n+3
t4=5-3n
Answered by
0
Answer:
hete a = 2 and d = -3
An = a + (n - 1)d
An = 2 + (n - 1)(-3)
An = 2 + (-3n+3)
An = 2 -3n + 3
therefore nth term An = 5 - 3n
Similar questions