Question

What is the number of mole of N-atoms in 18.066 * 10^23 nitrogen atoms?

Answer 1

∵ No. of atoms = Moles × NA

∴ Moles = No. of atoms / NA
  
             = 18.066×10²³  / 6.02×10²³
         
            = 3

Answer 2

Answer: The given number of nitrogen atoms occupies 3 moles.

Explanation:

We are given:

Number of nitrogen atoms = $18.066\times 10^{23}$

According to mole concept:

1 mole of a compound contains $6.022\times 10^{23}$ number of molecules.

So, using this concept:

As, $6.022\times 10^[23}$ number of atoms occupies 1 mole of a element.

So, $18.066\times 10^{23}$ number of atoms will have occupy $\frac{1mole}{6.022\times 10^{23}}\times 18.066\times 10^{23}=3mole$ of nitrogen element.

Thus, the given number of nitrogen atoms occupies 3 moles.