Question

What is the order of the surd (Cube root of 27)​

Answer 1

Answer:

It may be 9√27.

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Answer 2

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Solution:

∛3 = $3^{1/3}$

     = 3^$\frac{1 into 3}{3 into 3}$

     = 3$\frac{3}{9}$

     = $27^{1/9}$

     = $\sqrt[9]{27}$

∴ So, $\sqrt[9]{27}$ is the surd of order 9.