Question

What is the oxidation number of the metal for nh4 cr(nh3)2(ncs)4?

Answer 1

Oxidation number:

The oxidation number of an atom is zero in a neutral substance that contains atoms of only one element.

CN 6 OS+3

The coordination number of the given metal is 6

Oxidation number is +3

Answer 2

The oxidation number of chromium in the complex is +3

Explanation:

A coordination complex contains ligands that are bonded to the central metal atom or ion to form coordinate covalent bond. The ligands and the central metal together form the coordination sphere.

The given coordination complex is: $NH_4[Cr(NH_3)_2(NCS)_4]$

Central metal atom is Chromium (Cr)

Coordination sphere consists of 2 neutral ammonium ligands and 4 isothiocyabate ligand that carry -1 charge and as ammonium carries a +1 charge. So, the coordination sphere will carry -1 charge as the the coordination compound is electrically neutral.

Let the oxidation state of Cr be 'x'

Oxidation state of $NCS^-$ ligand = -1

Oxidation state of $NH_3$ ligand = 0

Evaluating the oxidation state of iron, we get:

$\Rightarrow x+2(0)+4(-1)=-1\\\\\Rightarrow x=+3$

Learn more about coordination number:

https://brainly.com/question/14077813

https://brainly.in/question/9041842

#learnwithbrainly