Question

What is the perimeter of the triangle with the vertices A (–4, 2), B(0, –1) and C(3, 3)?

Answer 1

Answer:

10+5√2

Step-by-step explanation:

Given:A (–4, 2), B(0, –1) and C(3, 3)

Now, distance between A and B=$\sqrt{4^{2}+(-3)^2 }=5$

Distance between A and C=$\sqrt{7^2+1^2}=5\sqrt{2}$

Distance between B and C=$\sqrt{3^2+4^2}=5$

(Note: we solved all the above equations using distance formula-)

Now Perimeter=AB+BC+CA=5+5+5√2=10+5√2