Question

What is the period of pendulum consisting of bob of mass 2g with length of pendulum 50cm.

Answer 1

Let period of pendulum be ( T ) = 2π ×√(L / g)
 L stands for length of pendulum 
 g stands for acceleration due to gravity
 
Here, L = 50cm 
            = 50 × 10⁻² m 
         g = 9.8 m/s²

∴ T = 2π √ [ ( 50 × 10⁻²) / 9.8 ]
      = 1.419 s //

Answer 2

Let period of pendulum be ( A ) = 2π ×√(L / g)
where
 L is for length of pendulum 
 g is for acceleration due to the gravity
 
now given that L = 50cm = 50 × 10⁻² m (changed in meter)
        and g = 9.8 m/s²

therefore A = 2π √ [ ( 50 × 10⁻²) / 9.8 ]
                   =6.28*0.22
                   =1.38