Question

What is the polar foam of " -3 " ??

Answer 1

Given: z=a+bi
r=√a^2+b^2
θ=π+tan ^ −1(b / a) 

(because it is quadrant 4)


z=r(cos(θ)+isin(θ)




z = -3 + 0.i

r = √(-3)^2 = 3


θ = π + tan ^-1 (0) = π


z = 3( cosπ + isinπ )