What is the potential difference between the terminal of a battery if 250J of work is required to flow the charge for 10seconds develop a current of 48 ampere.
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Key Point : Find the terminal potential difference in case of charging a battery.
According to question, it is the case of charging of battery. So, terminal potential difference is given by
TPD=VP−VR=E+Ir=2+(4×2) =10V....(i)
Again, VR−VQ=IR=4×4=16V....(ii)
From Eqs. (i) and (ii), we get
VP−VR+VR−VQ=10+16⇒VP−VQ=26V
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