the radius of two circle are 8 cm and 6 cm respectively find the radius of two circle having area equal to the sum of the areas of the two circles
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Let the radius of the first circle be r1
and second circle be r2.
third circle be R.
Given,
r1=8cm.r2=6cm.
A/q.
phi R^2=phi r1^2+phi r2^2.
phi R^2=phi(8^2+6^2).
R^2=64+36
R^2=100
R=10.
therefore the radius of the third circle of 10.CM.
HOPE IT HELPS YOU
sangwan46:
Thx
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