Question

what is the pressure at a depth of 15 cm in brine of density 1.2 g/cm3

Answer 1

Given
Density of brine (d) = 1.2 g/cm³

Pressure = hdg
= 0.15 m × 1.2 × 10³ kg/m³ × 9.8 m
= 1764 Pa

Pressure at that depth is 1764 Pascal

Answer 2

Given:

• Density of brine = 1.2 g/cm³

• Depth = 15 cm.

To find:

• Pressure at that depth ?

Calculation:

The pressure due to a fluid column at a particular depth is given by the general formula :

$\boxed{P = \rho \times g \times h}$

• $\rho$ is the density of the fluid, g is gravity and h is the depth from surface.

Now, we need to convert all the given values into SI UNIT :

• 1.2 g/cm³ = 1.2 × 1000 kg/m³ = 1200 kg/m³
• 15 cm = 15/100 = 0.15 metres
• g = 9.8 m/s².

Putting the values :

$\implies P = 1200 \times 9.8 \times 0.15$

$\implies P = 1764 \: Pascal$

So, pressure due to the fluid column at that depth is 1764 Pascal.