What is the probability of the dice by getting 8 as sum?
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When two dice are thrown, total possible outcomes = 6 × 6 = 36
Favorable outcomes = {(2, 6), (6, 2), (3, 5), (5, 3), (4, 4)}
∴ Number of favorable outcomes = 5
∴ P(getting a sum of 8)
= 536
Favorable outcomes = {(2, 6), (6, 2), (3, 5), (5, 3), (4, 4)}
∴ Number of favorable outcomes = 5
∴ P(getting a sum of 8)
= 536
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