Question

what is the probability that the spinner will not land on a multiple of 3?

Answer 1

Answer:

$\frac{3}{4}$ is the required probability not land on multiple of 3.

Step-by-step explanation:

Explanation :

Here we have a spinner marked from 1 to 8 continuously .

So, the number which is multiple of 3 from the given spinner  is 3 and 6 .

Total outcome = 8

∴The probability of multiple of 3 = $\frac{2}{8}$ = $\frac{1}{4}$

Now , the probability not land on a multiples of 3 = $1 - \frac{1}{4}$ = $\frac{3}{4}$

Final answer :

Hence , the probability not land on a multiple of 3 is $\frac{3}{4}$

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Answer 2

Answer:

answer is $3/4$.

Step-by-step explanation:

Given :- The wheel has 8 digits on it ,

To find :- The probability that the spinner will not land on multiple of 3 .

Solution :-

The numbers are , 1 ,2 , 3 , 4, 5 , 6 , 7 , 8 .

therefore , S = { 1,2,3,4,5,6,7,8}  ; n(S) = 8

multiple of 3 in the wheel are , 3 , 6

putting them set , A = { 3 , 6 }  , n(A) = 2

therefore , B( set not having multiple of 3 ) = { 1,2,4,5,7,8}

n(B) = n(S) - n(A) = 8-2 = 6

therefore , probability that spinner will not land on a multiple of 3 is

$6/8 \\3/4$

thus , answer is $3/4$.

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