What is the product of permeability of free space and permittivity?
Answers
Answered by
59
Hey.
Here is the answer.
With the magnetic permeability established, the electric permittivity takes the value given by the relationship
c = 1/sqrt(ε0μ0)
where the speed of light is given by
c=2.99792458 x 10^8 m/s (exact)
This gives a value of free space permittivity
ε0 = 8.854187817 x 10^-12 F/m
which in practice is often used in the form
k = 1/4piε0 = 8.987552 X10^9 Nm^2/C^2 = Coulomb's constant
So, product of permeability of free space and permittivity is 1/c^2.
Thanks.
Here is the answer.
With the magnetic permeability established, the electric permittivity takes the value given by the relationship
c = 1/sqrt(ε0μ0)
where the speed of light is given by
c=2.99792458 x 10^8 m/s (exact)
This gives a value of free space permittivity
ε0 = 8.854187817 x 10^-12 F/m
which in practice is often used in the form
k = 1/4piε0 = 8.987552 X10^9 Nm^2/C^2 = Coulomb's constant
So, product of permeability of free space and permittivity is 1/c^2.
Thanks.
Answered by
17
Answer:
c^-2
Explanation:
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