Question

What is the ratio of the area of a circle inscribed inside a rhombus with one angle as 60 degrees?

Answer 1

TO FIND: AC = ?

< A = 60°

=> triangle ABD is an equilateral triangle. as AB = AD hence base angles will be equal. & each will be of 60°

Hence smaller diagonal BD = 10 cm => BO = 10/2 = 5 cm

As, diagonals of a rhombus, bisect each other at right angles.

=> tri AOB is a right triangle with hypotenuse AB.

AB² = BO² + AO²

=> 10² = 5² + AO²

=> AO = √(100 - 25)

=> AO = √75 = 5√3 cm

=> 2AO = 10√3 cm

=> AC = 10√3 cm

Answer 2

sorry I didn't know this answer