Question

what is the right value ?​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

105

Step-by-step explanation:

The given numbers are in Arithmetic Progression [Common difference is same]

[You can check it by subtracting the preceding term from the succeeding term]

Total number of terms in the given arithmetic progression (n) = 10

[$a$] First Term = $10 . \frac{1}{11} => \frac{111}{11}$

[$a_{10}$] Last Term [10th Term] = $10 . \frac{10}{11} = > \frac{120}{11}$

Therefore, sum of the following numbers = Sum of the first 10 terms of the given A.P. [Arithmetic Progression] = $S_{10}$ [Sum of the first 10 terms]

$S_n = \frac{n}{2} [a + a_n]$

=> $\frac{10}{2} [\frac{111}{11} + \frac{120}{11}]$

=> $5. \frac{231}{11}$

=> 5 . 21

=> 105

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