Question

What is the smallest digit that must replace “?” in 126?8 such that it is divisible by both 2 and 3? *
please answer fast​

Answer 1

126?8=12618

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Answer 2

Answer:

1 should be in place of ? as accordingto divisiblity rule of 2 there should be an even number in ones digit and here 8 qualifies it . Now in divisiblity rule of 3 sum of all digits should be a multiple of 3

so lets add them

1 + 2 + 6 + 8 = 17

and 17 + 1 = 18 which is a multiple of 3

hope you like my answer thankyou