Question

What is the smallest number 1328 may be multipied by so that the product is a perfect square​

Answer 1

Answer:THIS IS FULL ALGIBRA

g^2 = 280^2 + 30^2 - 2*280*30*cos(90+40) g^2 = 280^2 + 30^2 - 2*280*30*cos(130°) g^2 = 78,400 + 900 - [16,800]*cos(130°) g^2 = 78,400 + 900 - [16,800]*[-0.642788] g^2 = 79,300 - [16,800]*[-0.642788] g^2 = 79,300 + [10,798.8384] g^2 = 90,098.8384 g = sqrt(90,098.8384) g = 300.16 mi/hr 300.16/sin(130)=30/sin(A) A=asin([30/300.16]*sin(130°)) A=asin(0.07656361039) A=4.391° 4.391°+40°= 44.391° ≈ 44° N 44° W

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Answer 2

Answer:

The number given is 1323. In order to find the smallest number to get a perfect cube we first need to factorize it.

⇒1323=

3×3×3

×

7×7

Since we need to find the cube root we group them in groups of three.

We need one 7 in order to complete the group.

Therefore the ans is 7.