Question

what is the smallest number by which 108 must be divided so that quotient is perfect cube

Answer 1

Prime factorization of 108 = 2*2*3*3*3

Hence, smallest number by which 108 must be divided so that quotient is perfect cube is 2*2=4

108=2*2*3*3*3

108/2*2=3*3*3

Answer 2

hey the answer is

108 = 2×2×3×3×3

as the factor 2 is not grouped.

2 must be multiplied 2 times, then divided from 108

So u should divide 4....

Hope it helps!!!