what is the smallest number by which 784 be multiplied so that the product become perfect cube? Also show the process
Answers
Answered by
15
Hello Dear!!!
Here's your answer...
The given number is
784
First,we have to do prime factorisation
784 - 2^4 * 7^2
Here,
The power of 2 is 4...
To become a perfect cube..then the power should be a multiple of 3
Then, it should be multiplied with two 2's to become power 6(multiple of 3)
And power of 7 is 2
It should be multiplied with one 7....to become power 3(power should be multiple of 3)
Then,
It should be multiplied with 2*2*7
28
Finally...it should be multiplied with 28 to get perfect cube
Verification -
784 * 28
21952
It is cube root of 28
______________________
Hope this helps you.....
Here's your answer...
The given number is
784
First,we have to do prime factorisation
784 - 2^4 * 7^2
Here,
The power of 2 is 4...
To become a perfect cube..then the power should be a multiple of 3
Then, it should be multiplied with two 2's to become power 6(multiple of 3)
And power of 7 is 2
It should be multiplied with one 7....to become power 3(power should be multiple of 3)
Then,
It should be multiplied with 2*2*7
28
Finally...it should be multiplied with 28 to get perfect cube
Verification -
784 * 28
21952
It is cube root of 28
______________________
Hope this helps you.....
Answered by
4
Answer:
784=2×2×2×2×7×7
784×2×2×7=2×2×2×2×2×2×7×7×7
784×28=21952
if we multiply 28 with 784, it becomes a perfect cube.
Similar questions