Question

What is the smallest number which when divided by 45 and 63 leaves a remainder 4 and 5?

Answer 1

seven as i think !!!

Answer 2

➡45-4 = 41

➡63-5 = 58

Smallest Number will be HCF

So find the HCF of 58 and 41

➡Therefore the HCF is 3 .

So the smallest number which when divided by 45 and 63 leaves remainder 4 and 5 is 3.

(^O^)❤Hope it helps ❤ (^O^)