Question

What is the solution to Negative three-fourths x + 2 less-than-or-equal-to negative 7?

Answer 1

Step-by-step explanation:

-3/4X +2 <= - 7

-3/4 X <= - 9 multiply equation by - 1 so sign changes

3/4 X >= 9

X>=12

Answer 2

Answer:

 $x \geq -12$

Step-by-step explanation:

$-\frac{3}{4} x + 2 \leq -7$

Multiply through by the LCM (4)

$-3x + 4 (2) \leq 4(-7)\\\\-3x + 8 \leq -28\\\\-3x \leq -28-8\\\\-3x\leq -36$

Divide both sides by -3

$x \geq -12$

NOTE: The sign changes when both sides are divided by a negative number.

HOPE THIS HELPS

PLEASE MARK AS BRAINLIEST