what is the specific gravity of the metal, if the weighs 6.5 kgf in air and 3. 5 and 3.5 kgf in water? Give the solution
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the body replaces a volume of water or air that has a weight difference of 3 units as Water gas a density of roughly 1000 kg/m^3. The volume is about 3 l. Therefore the density is 6,5 kg/3 l= 2,17 kg/l = 2167 kg/m^3.
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Answered by
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Answer:
2.166
Explanation:
- weight in air=6.5 kgf weight in water =3.5kgf 6.5-3.5=3 so that,6.5 ÷3=2.166
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