Question

what is the speed of a Broton with a de broglie wavelength of 0.1 A0[Mp=1.673x10-27kg]

Answer 1

The de-Broglie wavelength associated with a particle is given by λ = h / mv 
where h = Planck's constant = 6.626 * $10^{-34}$ Js
m = mass of the particle
v = velocity/speed of the particle

Hence, v = h / m λ

It is given in the data that:
λ = 0.1 A° = 0.1 * $10^{-10}$ m = 1 * $10^{-11}$ m
m = 1.673 * $10^{-27}$ kg

Substituting these values, we get 
v = ( 6.626 * $10^{-34}$ ) / (1.673 * $10^{-27}$ ) * ( 1 * $10^{-11}$ )
v = ( 6.626 * $10^{-34}$ ) / (1.673 * $10^{-38}$ )
Shifting the powers of 10 to the numerator, we get
v = ( 6.626 * $10^{38-34}$ ) / (1.673)
v = ( 6.626 * $10^{4}$ ) / (1.673)
v = 3.96 * $10^{4}$ m/s
v = 39,600 m/s or 39.6 km / s

Therefore, the speed of the proton is approximately 39,600 m/s.