what is the sum of 1st 20 terms of the progression 10,15,20.....than the next 20 terms?
Answers
Answered by
1
Common difference = 15 - 10 = 5
1 st term = 10 = a
20 th term = a + 19(d)
20th term = 10 + 19(5) = 10+95 = 105
=================
S(n) = [ first term + last term] × n/2
S(20) = [ 10 + 105] × 20/2
S(20) = 115 × 10
Sum of 1st 20 terms = 1150
I hope this will help you
(-;
Answered by
2
Heya !!!
AP = 10 , 15 , 20 ........ 20
Here,
First term ( A) = 10
Common Difference (D) = 5
Therefore,
Sum of first 20 terms =
=> Sn = N/2 × [ 2A + ( N-1) × D ]
=> S20 = 20/2 × [ 2 × 10 + (20-1) × 5) ]
=> 10 (20 + 19 × 5)
=> 10 ( 20 + 95)
=> 10 × 115
=> 1150.
HOPE IT WILL HELP YOU...... :-)
AP = 10 , 15 , 20 ........ 20
Here,
First term ( A) = 10
Common Difference (D) = 5
Therefore,
Sum of first 20 terms =
=> Sn = N/2 × [ 2A + ( N-1) × D ]
=> S20 = 20/2 × [ 2 × 10 + (20-1) × 5) ]
=> 10 (20 + 19 × 5)
=> 10 ( 20 + 95)
=> 10 × 115
=> 1150.
HOPE IT WILL HELP YOU...... :-)
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