Question

what is the sum of 2 consecutive numbers whose difference of whose square is 19

Answer 1

HELLO........FRIEND!!

THE ANSWER IS HERE,

Let the two consecutive numbers be x & x+1.

From the question,

$= > \: ({x + 1})^{2} - {x}^{2} = 19$

$= > \: {x}^{2} + 1 + 2x - {x}^{2} = 19$

$= > \: 2x + 1 = 19$

$= > 2x = 18$

$= > \: x = 9$
So, The two numbers are 9 & 10.

There sum => 9+10

=> 19.

:-)Hope it helps u.