what is the sum of the interior angles of a polygon having 9 sides??
Answers
Answered by
18
Hi friend!!
We know that,
The sum of interior angles of a polygon with n sides is 180(n - 2).
So, the sum of the interior angles of a polygon having 9 sides is 180(9-2)=180×7
=1260
I hope this will help you ;)
We know that,
The sum of interior angles of a polygon with n sides is 180(n - 2).
So, the sum of the interior angles of a polygon having 9 sides is 180(9-2)=180×7
=1260
I hope this will help you ;)
shifa42:
thankkkkkk uuuu
Answered by
4
we know that sum of interior angles in a polygon = (2n - 4)90° , where n is the number of sides
therefore , in polygon with 9 sides ,the sum oc interior angles will be
= (2×9 - 4)×90°
= (18 - 4)×90°
= 14 × 90°
= 1260°
hope this helps. ....
wiyh regards...
#Misa
therefore , in polygon with 9 sides ,the sum oc interior angles will be
= (2×9 - 4)×90°
= (18 - 4)×90°
= 14 × 90°
= 1260°
hope this helps. ....
wiyh regards...
#Misa
Similar questions