What is the sum of the squares of the first 20 natural numbers (1 to 20)?
Answers
Answered by
7
it can be done using the formula n(n+1)(2n+1)/6
where n is the last natural number
sum = 20(20+1)(40+1)/6
=2780
hope this helps you pls mark as best
where n is the last natural number
sum = 20(20+1)(40+1)/6
=2780
hope this helps you pls mark as best
Answered by
5
squares of numbers are
1 - 1
2 - 4
3 - 9
4 - 16
5 - 25
6 - 36
7 - 49
8 - 64
9 - 81
10 - 100
11 - 121
12 - 144
13 - 169
14 - 196
15 - 225
16 - 256
17 - 289
18 - 324
19 -361
20 - 400
sum of squares is 1+4+9+16+25+36+49+64+81+100+121+141+169+196+225+256+289+324+361+400
= 2867
1 - 1
2 - 4
3 - 9
4 - 16
5 - 25
6 - 36
7 - 49
8 - 64
9 - 81
10 - 100
11 - 121
12 - 144
13 - 169
14 - 196
15 - 225
16 - 256
17 - 289
18 - 324
19 -361
20 - 400
sum of squares is 1+4+9+16+25+36+49+64+81+100+121+141+169+196+225+256+289+324+361+400
= 2867
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N*(N+1)*(2N+1)/6
So putting N = 20 gives 2870.