what is the value of {1/(x+y)-1/(x-y)}
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Answered by
1
1/(x+y)-1/(x-y)
=[(x-y)-(x+y)]/x^2-y^2
=-2y/x^2-y^2
=[(x-y)-(x+y)]/x^2-y^2
=-2y/x^2-y^2
Answered by
0
{1/(x+y)-1/(x-y)}= {(x-y)-(x+y)/(x+y)(x-y)}
=x-y-x-y/x^2-xy+xy-y^2
=-2y/x^2-y^2
=x-y-x-y/x^2-xy+xy-y^2
=-2y/x^2-y^2
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