Question

What is the value of g(728) for the function below?

def g(y):
b = 0
while y >= 3:
(y,b) = (y/3,b+1)
return(b)

if u guys know about python pls help me plsss !!!!!

Answer 1

Answer:

5

Explanation:

y = 728

b = 0

while y >= 3:

(y,b) = (y/3,b+1)

print(b)

Output : 5

Hope this helps.

Answer 2

Concept:

While loop is also known as a loop that has been pre-tested. A while loop, in general, allows a section of code to be run many times depending on a boolean state. It can be thought of as a repeated if statement.

Given:

def g(y):

   b = 0

   while y >= 3:

       (y,b) = (y/3,b+1)

   return(b)

print(g(728))

Find:

What will be the value of g(728)?

Solution:

In each iteration value of y will be checked and then the following statements will get executed.

In the first iteration:

y = 242.66666666666666 and b = 1

In the second iteration:

y = 80.88888888888889 and b = 2

In the third iteration:

y = 26.962962962962962 and b = 3

In the fourth iteration:

y = 8.987654320987653 and b = 4

In the fifth iteration:

y = 2.995884773662551 and b = 5

Now the loop will end as y<3.

The final value of b will be 5.

∴ The value of g(728) = 5