Chemistry, asked by rukshar91, 10 months ago

what is the value of ln(2*10³)?and how to find the value of ln???

Answers

Answered by waqarsd
2
 log(ab) = log(a) + log(b) \\m log(a) = log( {a}^{m} ) \\ \\ log_{e}(10) =2.303 \\ log_{e}(2) = 0.693 \\ \\ log_{e}{(2 \times {10}^{3}) } \\ = log_{e}(2) + log_{e}( {10}^{3} ) \\ = log_{e}(2) + 3 log_{e}( {10}) \\ = 0.693 + 3(2.303) \\ = 7.602 \\
 <b > <red> You can find log values using log table
hope it helps...
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rukshar91: will you help me to use log table to find the value of log.. because I don't know how to use the table...
Answered by komalgoyal9625
1

In2*103 =2.303log 2*103


2.303*(3-0.3010)

2.303*2.699

6.2158.


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