Question

What is the value of n in the equation ? 1/2(n-4)-3=3-(2n+3)?

n = 0
n = 2
n = 4
n = 6

Answer 1

Answer:

n=. 2

Step-by-step explanation:

solved it finally u will get the ans

Answer 2

The required "option (2) n = 2" is correct.

Step-by-step explanation:

The given  equation is:

$\dfrac{1}{2}(n-4)}-3= 3-(2n+3)$

To find, the value of n in the given equation = ?

∴ $\dfrac{1}{2}(n-4)}-3= 3-(2n+3)$

⇒ $\dfrac{n}{2}-\dfrac{4}{2} -3= 3-(2n+3)$

⇒ $\dfrac{n}{2}-2-3= 3-(2n+3)$

⇒ $\dfrac{n}{2}-5= 3-2n-3$

⇒ $\dfrac{n}{2}-5= -2n$

⇒ $\dfrac{n}{2}+2n=5$

⇒ $\dfrac{n+4n}{2}=5$

⇒ 5n = 10

⇒ n = 2

Thus, the required "option (2) n = 2" is correct.