Question

What is the value of Q so that Electric potential in the square at Point P becomes zero​

Answer 1

Answer:

option b

Explanation:

-q√2

now make as a brainliest

Answer 2

Concept:

• Electric potential

Given:

• Charges -q, 2q at two corners
• length of the side of each square = a
• Charge at point P = 0

Find:

• Value of Q

Solution:

Electric potential = kq/r

Potential at P due to charge 2q = 2kq/a           (r=a)

Potential at P due to charge -q = -kq/a              (r=a)

To find the potential at P due to charge Q, we need to find the distance between point P and Q.

Distance between point P and Q = $\sqrt{a^{2} + a^{2} }$ = a√2

Potential at P due to charge Q = kQ/a√2              (r=a√2)

Potential at P due to all charges = sum of the potential of charges due to Q, 2q, -q

Potential at P due to all charges = 0

Potential at P due to all charges = 2kq/a + (-kq/a ) + kQ/a√2    

Potential at P due to all charges = kq/a + kQ/a√2    

Potential at P due to all charges = √2 kq/a√2  + kQ/a√2  

Potential at P due to all charges = (√2 kq + kQ)/a√2  

(√2 kq + kQ)/a√2 = 0

√2 q + Q = 0

Q = -√2q

The value of Q is -√2q.

#SPJ2