Question

What is the value of this equation ---) 2x:3y:4z​

Answer 1

We should find a point and direction vector from the equation

2x=3y=4z

divide them by 12,

x/6 = y/4 = z/3 = c ( const)

any coordinate in the line is of the form(6c,4c,3c)

if c=0, then (0,0,0) is a point in the line,

we can write the equation in the vector form as

P=(0,0,0)+s∗(6,4,3) where s is a scale factor.

or simply

P=s∗(6,4,3)

i.e. P=s∗(6i⃗ +4j⃗ +3k⃗ )

Please mark me as brainliest.