What is the value of volume coefficient for ideal gas?
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The temperature drop of a gas divided by its pressure drop under constantenthalpy conditions is called the Joule-Thomson coefficient (JTC) of the gas. The JTC of an ideal gas is equal to zero since its enthalpy depends on only temperature.
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Considering the gas to be ideal,we use pv=nRT
Let's assume volume expansion coefficient of gas to be a
So a=(1/v)(dv/dT). (Equation 1)
Considering pressure to be constant,let's differentiate ideal gas equation wrt to T
So we get p(dv/dT)=nR
Hence dv/dT=nR/p (equation 2)
Substitute equation 2 in equation 1
And eleminate 1/v in equation 1 using the ideal gas equation
So final answer is a=1/T(where a is volume expansion coffecient)
Let's assume volume expansion coefficient of gas to be a
So a=(1/v)(dv/dT). (Equation 1)
Considering pressure to be constant,let's differentiate ideal gas equation wrt to T
So we get p(dv/dT)=nR
Hence dv/dT=nR/p (equation 2)
Substitute equation 2 in equation 1
And eleminate 1/v in equation 1 using the ideal gas equation
So final answer is a=1/T(where a is volume expansion coffecient)
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