Math, asked by shahaekta82, 7 months ago

what is the value of x²+y²+xy upon x²-y²when x=16 and y is equal to 5​

Answers

Answered by gargparth812
1

Step-by-step explanation:

HERE IS YOUR ANSWER...

USED (A+B)² AND A²-B²=(A+B)(A-B) FORMULA TO MQKE CALCULATION EASY

Attachments:
Answered by harshdeepsinghbasra1
0

Answer:

Given: x=16; y=5

 {x}^{2}  +   {y}^{2}  + xy = ( {x + y)}^{2}

Therefore.

++xy upon -y²

can be written as

(x+y)² upon x²-

(16+5)² upon 16²-5²

21² upon 256-15

441 upon 241 Ans

HOPE it helps you......

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