Question

What is the voltage of n electrolytic cell with nicel and coper electrodes/?

Answer 1

The voltage is the cell's electromotive force derived from the reduction potentials of each cell, here we have,

Ni2+(aq)+2e−→Ni(s) where E=−0.23V
Cu2+(aq)+2e−→Cu(s) where E=0.34V

Quantitatively, this is saying copper ions are more easily reduced than nickel ions. Hence, the cell's reaction would be,

Cu2+(aq)+Ni(s)⇌Ni2+(aq)+Cu(s), where

E=Ered−Eox
∴E∘=0.57V

Answer 2

heya


The voltage is the cell's electromotive force derived from the reduction potentials of each cell, here we have,

Ni^(2+)(aq) + 2e^(-) to Ni(s) where E = -0.23V
Cu^(2+)(aq) + 2e^(-) to Cu(s) where E = 0.34V

Quantitatively, this is saying copper ions are more easily reduced than nickel ions. Hence, the cell's reaction would be,

Cu^(2+)(aq) + Ni(s) rightleftharpoons Ni^(2+)(aq) + Cu(s), where

E = E_("red") - E_("ox")



HOPE HELPED