Question

What is the weight of oxygen required for the complete
combustion of 2.8 kg of ethylene

(a) 2.8 kg
(b) 6.4 kg
(c) 9.6 kg
(d) 96 kg​

Answer 1

Answer:

Combustion of Ethylene can be written as:

C2H4 + 3 O2 → 2 CO2 + 2 H2O

0.028 kg (Molar mass of ethylene) needs 3 x 0.032 = 0.096 kg of oxygen.

1 kg of ethylene will need (0.096/0.028) =  3.42 kg of oxygen.

So, 2.8 kg of ethylene will need (3.42 x 2.8) =  9.6 kg of oxygen

So answer is (c) 9.6 kg