Question

What is the work done in an open vessel at 300 K, when 112 g of iron reacts with dilute HCl ??

Answer 1

w=p(change in volume)
w=p(nrt/p)
n=p(2*2*300/p)=1200calorie

Answer 2

Explanation:

It is known that number of moles equal mass divided by molar mass.

As it is given that mass is 112 g and molar mass of iron is 56 g/mol.

Therefore, calculate number of moles as follows.

                  No. of moles = $\frac{mass}{molar mass}$

                                         = $\frac{112 g}{56 g/mol}$

                                         = 2 mol

Also, it is known that work done = P $\Delta V$

As it is known that PV = nRT according to ideal gas equation and value of R equals 2 cal/K/mol.

So,        W = P $\Delta V$

                 = nRT

                 = $2 mol \times 2 cal/K/mol \times 300 K$  

                 = 1200 cal

Thus, we can conclude that the work done in given open vessel is 1200 cal.