what is the work to be done to increase the velocity from 18 km/hr to 19 km/hr
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m=2000kg
u=18km/hr=5m/s
v=19=5.3m/s
wd=1/2mv^2-1/2mu^2
=300 j
PRATHAMABD:
is it important to change in m/sec
Answered by
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Given:
Initial velocity u=18km/h=5m/s
Final velocity v=19km/h=5.278m/s
Mass of the car m=2000kg
To find:
Work done in increasing the velocity of the car from uto v.
Solution:
Let Wbe the work and ΔK=Kf−Kibe the increase in kinetic energy. (Here Kfand Kiare the final and initial kinetic energies respectively.)
From the work-energy theorem, we know that the work done will equal the change in kinetic energy. That is W=K.
Kinetic energy of a particle K=12mv2
Hence, the increase in kinetic energy can be found by subtracting the initial kinetic energy from the final kinetic energy
K=12mv2−12mu2
=> 12m(v2−u2)
= 12(2000)(5.2782−52)
= 5714.5682
= 2854.28J.
hope it will help you
Initial velocity u=18km/h=5m/s
Final velocity v=19km/h=5.278m/s
Mass of the car m=2000kg
To find:
Work done in increasing the velocity of the car from uto v.
Solution:
Let Wbe the work and ΔK=Kf−Kibe the increase in kinetic energy. (Here Kfand Kiare the final and initial kinetic energies respectively.)
From the work-energy theorem, we know that the work done will equal the change in kinetic energy. That is W=K.
Kinetic energy of a particle K=12mv2
Hence, the increase in kinetic energy can be found by subtracting the initial kinetic energy from the final kinetic energy
K=12mv2−12mu2
=> 12m(v2−u2)
= 12(2000)(5.2782−52)
= 5714.5682
= 2854.28J.
hope it will help you
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