Question

What is value of [(3 x 3 x 3 x 3 x 3 x 3)^6 ÷ (3 x 3 x 3 x 3)^7 x 3^4]?​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

[(3 x 3 x 3 x 3 x 3 x 3)^6 ÷ (3 x 3 x 3 x 3)^7 x 3^4]

= [$(3^{6} )^{6}$ ÷ $(3^{4} )^{7}$×$3^{4}$]                           [∵ $(a^{2} )^{2} = a^{2*2}$]

= [$3^{6*6}$ ÷ 3^{4*7} * 3^4]

= [$3^{36}$ ÷ $3^{28}$ × $3^{4}$]                       [∵B.O.D.M.A.S rule]  (First division)

= $3^{36-28}$ × $3^{4}$                           [∵$a^{x}$÷ $a^{y}$ = $a^{x-y}$]

= $3^{8}$×$3^{4}$                             [∵ $a^{x}$×$a^{y}$ = $a^{x+y}$]

= $3^{8+4}$

= $3^{12}$

= 531441 (Ans)