What length of tarpaulin 3 m wide will be required to make a conical tent of height 8 m and base radius 6 m? Assume that the extra length of material will be required for stitching margins and wastage in cutting is approximately 20 cm. (Use π=3.14).
Answers
Length of tarpaulin required = 63 m
Given :-
- Height = 8 m
- Base Radius = 6 m
Find the value of l :-
l² = h² + r²
= (8)² + (6)²
= 64 + 36
= 100
l = 10 m
CSA of conical tent = πrl
Substitute the values in this formula :-
CSA = 3.14 x 6 x 10
= 188.4 m²
Now, let's calculate the length of tarpaulin required
Area of tarpaulin required = Area of tent
l x b = 188.4 m²
l x 3 = 188.4 m²
l = 188.4/3 = 62.8 m
Margin given = 20 cm = 0.2 m
∴ Total length = 62.8 + 0.2
= 63 m
Answer:
Length of tarpaulin required = 63 m
Given :-
Height = 8 m
Base Radius = 6 m
Find the value of l :-
l² = h² + r²
= (8)² + (6)²
= 64 + 36
= 100
l = 10 m
CSA of conical tent = πrl
Substitute the values in this formula :-
CSA = 3.14 x 6 x 10
= 188.4 m²
Now, let's calculate the length of tarpaulin required
Area of tarpaulin required = Area of tent
l x b = 188.4 m²
l x 3 = 188.4 m²
l = 188.4/3 = 62.8 m
Margin given = 20 cm = 0.2 m
∴ Total length = 62.8 + 0.2
= 63 m