what mass of NH4oH will be needed to prepare 250ml of 20m solution
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Explanation: My question is this x-x-1/2=1-x-2/3 give me a answer and I give a answer of your question
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Explanation:
Molarity = moles of solute/ volume of solution (in litres)
20= moles × 1000/ 250
20 = moles × 4
moles of NH₄OH = 5 mole
molar mass of NH₄OH = 14 + 1 × 4 + 16 + 1 (∵ N = 14, H= 1, O= 16)
= 14 +4 + 16 + 1
=35 g
moles = mass/ molar mass
5= mass of NH₄OH/ 35
mass of NH₄OH = 5 × 35
mass of NH₄OH = 175 g
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