Question

What must be added to 7z3-11z2-129 to get 5z2+7z-92?

Answer 1

$\huge\mathbb{\fcolorbox{aqua}{red}{\fcolorbox{aqua}{orange}{ANSWER....!!!}}}$

LET THE NUMBER ADDED BE ' X ' ......

SO,

$7 {z}^{3} - 11 {z}^{2} - 129 + x = 5{z}^{2} + 7z - 92 \\ \\ x = 5 {z}^{2} + 7z - 92 - (7 {z}^{3} - 11 {z}^{2} - 129) \\ \\ x = 5 {z}^{2} + 7z - 92 - 7 {z}^{3} + 11 {z}^{2} + 129 \\ \\ x = - 7 {z}^{3} + 5 {z}^{2} + 11 {z}^{2} + 7z - 92 + 129 \\ \\ x = - 7 {z}^{3} + 16 {z}^{2} + 7z + 37$