Question

What must be added to x3 – 3x2 – 12x + 19 so that the result is exactly divisible by x2 – x + 6? ​

Answer 1

Answer:

Let the number to be added be x

x^3-3x^2-12x+10. + X= x^2-x+6

X= x^2-x+6-[x^3-3x^2-12x+10]

X=x^2-x+6-x^3+3x^2+12x-10

Gather the same terms

X=x^2+3x^2-x+12x+6-10-x^3

X=4x^2-11x-4-x^3